A solid metallic toy has a hemispherical base with radius 3.5 cm surmounted by a cone. If the height of the cone is the same as the radius of its base, then the volume of metal used in $$cm^{3}$$ is: (Take $$\pi=\frac{22}{7}$$)

A

$$89\frac{2}{3}$$ $$cm^{3}$$

B

$$144\frac{3}{4}$$ $$cm^{3}$$

C

$$134\frac{3}{4}$$ $$cm^{3}$$

D

$$179\frac{2}{3}$$ $$cm^{3}$$