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Question 69
A alone can complete a work in 10 days and B alone can complete the same work in 20 days. In how many days both 4 and B together can complete half of the total work?
Solution
Let the total work be 20 units (LCM of 10 and 20)
Efficiency of A = 20/10 = 2 units per day
Efficiency of B = 20/20 = 1 unit per day
Total efficiency of A and B = 3 units per day
Half of the work = 20/2 = 10 units.
Hence, 10 units can be completed by A and B together in $$\dfrac{10}{3}$$ days.
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