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Question 68
Working together A, B and C can complete a piece of work in 24 days. After working together for 4 days. C left the work. A and B completed the remaining work in 30 days. The number of days taken by C alone to complete the same work is:
Solution
Let the total work be 48 units
Number of units of work they together do on each day=48/24 =2 units
In 4 days they together do 4*2=8 units of work
So 48-8=40 units is left
This is done by A and B in 30 days and so their combined efficiency=40/30
=4/3
In each day CÂ can do 2-(4/3)=2/3 units
So 48 units is done in 48*3/2=72 days Â
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