SSC GD 11th March 2019 Shift-3

Question 68

The value of $$24 \div 4 \times (3 + 3) \div 2$$ is:

Solution

$$24 \div 4 \times (3 + 3) \div 2 = \dfrac{24}{4} \times \dfrac{6}{2} = 18$$

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