Question 68

The average marks of 40 students was foundto be 68. If the marks of two students were incorrectly entered as 48 and 64 instead of 84 and 46 respectively, then what is the correct average?

Solution

Share

According to the question,

Required average = $$\frac{\left(40\times\ 68+130-112\right)}{40}=\frac{2738}{40}=68.45$$

Was this solution helpful?

Get AI Help

View More Questions From Average, Ratio, and Proportions

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

Free SSC Quant Questions

SSC Data InterpretationSSC GeometrySSC Linear EquationsSSC Number SystemsSSC Quadratic EquationsSSC TrigonometrySSC AgesSSC Arithmetic

Join CAT 2026 course by 5-Time CAT 100%iler

Start your IIM journey with the right preparation and crack CAT 2026.

Enroll Now
Ask AI