Question 67
From a point P outside a circle, PAB is a secant and PTis a tangent to the circle, where, A, B and T are points on the circle. If PT = 5 cm, PA = 4 cm and AB = x cm,then x is equal to:
Solution
According to the questionÂ
PT = 5cm , PA = 4cm , AB = xcmÂ
$$PA\times PT = PT^2$$
4(4+x) = $$5\times5$$
4+x =Â $$\frac{25}{4}$$
x = $$\frac{9}{4}$$=2.25 cm
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