Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 68
Let f(x)= $$\max(5x, 52-2x^2)$$, where x is any positive real number. Then the minimum possible value of f(x)
Correct Answer: 20
Solution
The minimum value of the function will occur when the expressions inside the function are equal.
So, 5$$x$$ = $$52 - 2x^2$$
or, $$2x^2 + 5x - 52$$ = 0
On solving, we get $$x$$ = 4 or $$-\dfrac{13}{2}$$
But, it is given that $$x$$ is a positive number.
So, $$x$$ = 4
And the minimum value = 5*4 = 20
Hence, 20 is the correct answer.
Video Solution
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 35+ CAT previous year papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Venn Diagrams QuestionsCAT Remainders QuestionsCAT Number Series QuestionsCAT Logarithms, Surds and Indices QuestionsCAT Simple Interest Compound Interest Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Data Interpretation Basics QuestionsCAT Truth Lie Concept QuestionsCAT Maxima-Minima QuestionsCAT 2D & 3D LR QuestionsCAT Charts Questions
