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If $$\tan x = \cot(60^\circ + 6x)$$,then what is the value of x ?
$$\tan x = \cot(60^\circ + 6x)$$
$$\cot (90^\circ - x) = \cot(60^\circ + 6x)$$
7x = $$30^\circ$$
x = $$\frac{30^\circ}{7}$$
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