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If $$\tan x = cot (65^\circ + 9x)$$, then what is the value of x ?
$$\tan x = cot (65^\circ + 9x)$$
that means,
$$cot (90^\circ - x) = cot (65^\circ + 9x)$$
Hence,
$$(90^\circ - x) = (65^\circ + 9x)$$
Hence, x = $$2.5^\circ$$
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