Question 68

Each side of a square is 12 cm long. The perimeter of this square is equal to the perimeter of a rectangle whose length is 16 cm. What will be the area of this rectangle?

Solution

Let's assume the each side of a square is 'a'.

Let's assume the length and breadth of a rectangle are 'L' and 'B'.

Each side of a square is 12 cm long. The perimeter of this square is equal to the perimeter of a rectangle whose length is 16 cm.

$$4 \times a = 2(L+B)$$

$$4 \times 12 = 2(16+B)$$

$$48 = 2(16+B)$$

16+B = 24

B = 24-16 = 8 cm

Area of this rectangle = $$L\times B$$

= $$16\times8$$

= 128 $$cm^2$$

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