$$\triangle ABC$$ is a right-angle triangle at B and $$\tan A = \frac{3}{4}$$, then $$\sin A + \sin B + \sin C$$ will be equal to:

A

$$2\frac{4}{5}$$

B

$$2\frac{2}{5}$$

C

$$3\frac{1}{5}$$

D

$$1\frac{1}{5}$$