In a city 60% of the population are males and the rest are females. If the ratio of married males to non-married males is 5 : 7, and the ratio of married females to non-married females is 2: 3, then what percentage of the total population is married?

Let's assume the total population is 100y.

In a city 60% of the population are males and the rest are females.

Male population = 100y of 60% = 60y

Female population = 100y-60y = 40y

If the ratio of married males to non-married males is 5 : 7.

Married Male population = $$60y\times\frac{5}{5+7}$$

= $$60y\times\frac{5}{12}$$

= $$5y\times5$$

= 25y

The ratio of married females to non-married females is 2: 3.

Married female population = $$40y\times\frac{2}{2+3}$$

= $$40y\times\frac{2}{5}$$

= $$8y\times2$$

= 16y

Percentage of the total population is married = $$\frac{marrid\ population}{total\ population}\times100$$

= $$\frac{25y+16y}{100y}\times100$$

= $$\frac{41y}{100y}\times100$$

= 41%