Question 67
A shopkeeper bought a machine for ₹4600 and spent ₹500 on its repairs and transport. He marked the machine at 8% above the over all cost price. If he sold the machine for ₹4681.80 after giving x% discount, then the value of x is:
Solution
Total cost price = 4600 + 500 = ₹5100
Marked price = $$\frac{108}{100}\times5100$$ = ₹5508
Discount = x%
Selling price = ₹4681.80
$$\frac{100-x}{100}\times5508=4681.80$$
100 - x = $$\frac{468180}{5508}$$
100 - x = 85
x = 15
Hence, the correct answer is Option A
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