A circle is inscribed in $$\triangle$$ ABC, touching AB, BC and AC at the points P, Q and R, respectively. If AB - BC = 4 cm, AB -AC= 2 cm and the perimeter of $$\triangle$$ ABC = 32 cm , then $$\frac{BC}{2}$$ (in cm)=?

A

$$\frac{11}{3}$$

B

$$\frac{10}{3}$$

C

$$\frac{13}{3}$$

D

$$\frac{20}{3}$$