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Question 66
What is the value of $$\frac{5}{12} \times \frac{7}{12} \div \left(\frac{1}{75} + \frac{5}{12} of \frac{36}{25}\right) + \frac{4}{5} \times \frac{75}{16}$$
Solution
= $$\frac{5}{12}\times\frac{7}{4}\times\frac{25}{46}+\frac{15}{4}$$
= $$\frac{875}{2208}+\frac{15}{4}$$
= $$\frac{875+8280}{2208}$$
= $$\frac{9155}{2208}$$
=Â $$\frac{5}{12} \times \frac{7}{12} \div \left(\frac{1}{75} + \frac{5}{12} of \frac{36}{25}\right) + \frac{4}{5} \times \frac{75}{16}$$
=Â $$\frac{5}{12}\times\frac{7}{12}\div\left(\frac{1}{75}+\frac{5}{12}\times\frac{36}{25}\right)+\frac{4}{5}\times\frac{75}{16}$$
=Â $$\frac{5}{12}\times\frac{7}{12}\div\left(\frac{1}{75}+\frac{3}{5}\right)+\frac{4}{5}\times\frac{75}{16}$$
= $$\frac{5}{12}\times\frac{7}{12}\div\left(\frac{46}{75}\right)+\frac{15}{4}$$= $$\frac{5}{12}\times\frac{7}{4}\times\frac{25}{46}+\frac{15}{4}$$
= $$\frac{875}{2208}+\frac{15}{4}$$
= $$\frac{875+8280}{2208}$$
= $$\frac{9155}{2208}$$
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