Solution
= $$2 - 2 \div 2 \times 2 + 2 (2 of 2 - 2 - 2 \div 2)$$
= $$2-\frac{2}{2}\times2+2(2\times2-2-\frac{2}{2})$$
= $$2-1\times2+2(4-2-1)$$
= $$2-2+2(4-3)$$
= $$2\times\ 1$$
= 2
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