Question 66

What is the value of $$2 - 2 \div 2 \times 2 + 2 (2 of 2 - 2 - 2 \div 2)$$?

Solution

= $$2 - 2 \div 2 \times 2 + 2 (2 of 2 - 2 - 2 \div 2)$$

= $$2-\frac{2}{2}\times2+2(2\times2-2-\frac{2}{2})$$

= $$2-1\times2+2(4-2-1)$$

= $$2-2+2(4-3)$$

= $$2\times\ 1$$

= 2

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