Question 66
What is the simplified value of $$1\frac{1}{16}-(\frac{2}{5} of\frac{5}{32})-\frac{1}{3}\div\frac{3}{7}$$ of$$\frac{49}{50}+2-(4\times19)\div63$$?
Solution
= $$1\frac{1}{16}-(\frac{2}{5} of\frac{5}{32})-\frac{1}{3}\div\frac{3}{7}$$ of$$\frac{49}{50}+2-(4\times19)\div63$$
= $$\frac{17}{16}-\frac{1}{16}-\frac{1}{3}\div\frac{21}{50}+2-\frac{76}{63}$$
= $$\frac{16}{16}-\frac{1}{3}\times\frac{50}{21}+2-\frac{76}{63}$$
= $$1-\frac{50}{63}+2-\frac{76}{63}$$
= $$3-\frac{126}{63}$$
= 3-2
= 1
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