Two circles touch each other externally. The distance between their centres is 8 cm. If the radius of one circle is 3 cm, then the radius of the other circle is:
Two circles touch externally at point D as shown in figure
Radius of smaller circle = BD = 3 cm
Distance between the centres of the circles = 8 cm
$$\Rightarrow$$ AB = 8
$$\Rightarrow$$ AD + BD = 8
$$\Rightarrow$$ AD + 3 = 8
$$\Rightarrow$$ AD = 5 cm
$$\therefore\ $$Radius of other circle = AD = 5 cm
Hence, the correct answer is Option A
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