Question 66

The value of $$\sqrt{3\frac{1}{16}} + \frac{1}{2} - \frac{3}{4} = $$

Solution

$$ = \sqrt{3\frac{1}{16}} + \frac{1}{2} - \frac{3}{4}$$

$$=\sqrt{\frac{49}{16}}+\frac{1}{2}-\frac{3}{4}$$

$$=\frac{7}{4}+\frac{1}{2}-\frac{3}{4}$$

$$=\frac{7}{4}-\frac{3}{4}+\frac{1}{2}$$

$$=\frac{4}{4}+\frac{1}{2}$$

$$= 1+\frac{1}{2}$$

$$= 1\frac{1}{2}$$

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