Solution
$$\frac{[54-(5 \div 2)\times 8]+13}{48-4 \div 3 \times 8-2}$$
= $$\frac{[54-(2.5)\times 8]+13}{48-4 \times \frac{1}{3} \times 8-2}$$
= $$\frac{[54-20]+13}{48- \frac{32}{3} -2}$$
= $$\frac{47}{\frac{106}{3}}$$
= $$\frac{141}{106}$$
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