Simplify the following expression $$\left[8\times5-3 of \left(2\frac{3}{5}\div1\frac{2}{5}\times5-3\right)\right]\times\frac{7}{2}$$.

Given Equation : $$\left[8\times5-3 of \left(2\frac{3}{5}\div1\frac{2}{5}\times5-3\right)\right]\times\frac{7}{2}$$.

Lets solve this according to the rule of BODMAS

$$\left[8\times5-3of\left(\frac{13}{7}\times5-3\right)\right]\times\frac{7}{2}.$$

$$\left[8\times5-3of\left(\frac{44}{7}\right)\right]\times\frac{7}{2}.$$

$$\left[40-\frac{132}{7}\right]\times\frac{7}{2}.$$

$$\left[\frac{148}{7}\right]\times\frac{7}{2}.$$

= 74

Hence , Option B is correct.