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An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) : $$(m_e = 9 \times 10^{-31} kg)$$
$$12.2 \times 10^{-12}m$$
$$12.2 \times 10^{-14}m$$
$$12.2 nm$$
$$12.2 \times 10^{-13}m$$
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