When an integer n is divided by 8, the remainder is 3. What will be the remainder if 6n-1 is divided by 8 ?
Let the quotient is q,
$$n=8q+3$$-----------(i)
Now, multiplying 6 in the equation (i)
$$\Rightarrow 6n=48q+18$$
$$\Rightarrow 6n=8(6q+2)+2$$
$$\Rightarrow 6n-1=8(6q+2)+1$$
Hence, remainder will be 1.
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