Question 65
In $$\triangle ABC$$, if $$AB = AC$$ and $$\angle BAC = 40^\circ$$, then the measure of $$\angle B$$ is:
Solution
By the property,
When AB = AC then $$\angle ABC = \angle ACB$$
We know that,
$$\angle ABC + \angle ACB + \angle BAC = 180^\circ$$
$$2\angle ABC = 180^\circ - 40^\circ$$
$$\angle ABC = 140/2 = 70^\circ$$
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