We know that, $$sin(x+y) = sinxcosy + cosxsiny$$ --------(i)
and $$sin(x-y) = sinxcosy-cosxsiny$$ ------------(ii)
Adding equations (i) and (ii), we get :Â
$$sin(x+y) + sin(x-y) = 2sinxcosy$$ ------------(iii)
Let $$x + y = C$$ and $$x - y = D$$
=> $$x = \frac{C+D}{2}$$
and $$y = \frac{C-D}{2}$$
Substituting above values in equation (iii)
=> $$sinC + sinD = 2sin(\frac{C+D}{2})cos(\frac{C-D}{2})$$
=> Ans - (B)
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