Question 65

If 4!4 = 80, 3!8 = 110 and 6!2 = 80, then find the value of 7!9 = ?

Solution

Given : 4!4 = 80, 3!8 = 110 and 6!2 = 80

If we replace '!' with '+', and multiply the sum by 10, we get the desired result.

Eg :- $$(4+4)\times10=80$$

and $$(3+8)\times10=110$$ and $$(6+2)\times10=80$$

Similarly, $$(7+9)\times10=160$$

=> Ans - (D)

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