Solution
Given : 4!4 = 80, 3!8 = 110 and 6!2 = 80
If we replace '!' with '+', and multiply the sum by 10, we get the desired result.
Eg :- $$(4+4)\times10=80$$
and $$(3+8)\times10=110$$ and $$(6+2)\times10=80$$
Similarly, $$(7+9)\times10=160$$
=> Ans - (D)
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