SSC CHSL 11 July 2019 Shift-2

Question 65

For $$ 0^\circ < \theta < 90^\circ$$, $$tan\theta + cot\theta$$ = 2 is equal to:

Solution

If $$tan\theta + cot\theta$$ = 2

Then $$\tan\theta+\frac{1}{\tan\theta\ }=2$$

If the sum of a number and its reciprocal = 2

then the number is equal to 1

So, $$\tan\theta\ =1=45^{^{\circ\ }}$$ 


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