Question 65

Find the sum of the measures all the interior angles of a polygon having 10 sides.

Solution

Sum of all interior angles of a polygon having $$n$$ sides = $$(n - 2) \times 180$$°

Number of sides of polygon, $$n = 10$$

=> Sum of interior angles = $$(10 - 2) \times 180$$°

= $$8 \times 180 = 1440$$°

=> Ans - (C)

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