Question 64

What is the average of first 9 even numbers?

Solution

Sum of first $$n$$ even numbers = $$n(n+1)$$

=> Average of first $$n$$ even numbers = $$\frac{n(n+1}{n}=(n+1)$$

$$\therefore$$ Average of first 9 even numbers = $$(9+1)=10$$

=> Ans - (D)

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