Question 64

The population of a town increases by 8% every year. If the present population of the town is 14,580, then what was the population of the town 2 years ago?

Solution

Let's assume the population of the town 2 years ago was 'y'.

The population of a town increases by 8% every year. If the present population of the town is 14,580.

y of (100+8)% of (100+8)% = 14580

y of 108% of 108% = 14580

$$y\times\frac{108}{100}\times\frac{108}{100}=14580$$

$$y\times\frac{11664}{10000}=14580$$

11664y = 145800000

y = 12500

the population of the town 2 years ago = 12500

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