Question 64

The approximate value of $$(4488 \div 11.01 - 7.98) \div 15.99$$ is:

Solution

$$\ \frac{\frac{4488}{11.01}-7.98\ }{15.99}$$

$$\ \frac{\frac{4488}{11}-8}{16}$$

$$\ \frac{408-8}{16}$$

$$\ \frac{400}{16}$$

$$\ 25$$

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