In $$\triangle$$ ABC , AB= 7 cm, BC= 10 cm, and AC = 8 cm. If AD is the angle bisector of $$\angle$$ BAC, where D is a point on BC, then DC (in cm)=?

A

$$\frac{14}{3}$$

B

$$\frac{17}{3}$$

C

$$\frac{16}{3}$$

D

$$\frac{11}{3}$$