In the given figure AB = DB and AC = DC. If $$\angle ABD = 58^{\circ}$$ and $$\angle BDC = (2X - 4)^{\circ},\angle ACB = (x + 15)^{\circ}$$ and $$\angle DCA = 63^{\circ}$$.

A

259

B

325

C

268

D

273