A man walks at the rate of Skm/hour, he misses a train by 7 minutes. However,if he walks at the rate of Gkm/hour, he reaches the station 5 minutes before the arrival of the train. The distance covered by him to reach the station is
Lets assume the required distance = x km.
Difference in the times taken at two speeds=12mins=1/5 hr.
Therefore (x/5-x/6)=1/5 or (6x-5x) = 6 or x = 6km.
So required distance = 6 km
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