Which least number when divided by 12, 15, 20 and 54 leaves a remainder 8 in each case?
LCM of 12, 15, 20, 54
12 = 2 x 2 x 3
15 = 3 x 5
20 = 2 x 2 x 5
54 = 2 x 3 x 3 x 3
LCM = 27 x 4 x 5 = 27 x 20
= 540
ADD 8
= 540 + 8 = 548
So, C is correct choice.
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