Question 63

What is the slope of the line perpendicular to the line passing through the points (8,­2) and (3,­1)?

Solution

Slope of line passing through $$(x_1,y_1)$$ and $$(x_2,y_2)$$ is $$\frac{y_2 - y_1}{x_2 - x_1}$$

=> Slope of line passing through (3,1) and (8,2) = $$\frac{2 - 1}{8 - 3} = \frac{1}{5}$$

Let slope of line perpendicular to it = $$m$$

Also, product of slopes of two perpendicular lines = -1

=> $$m \times \frac{1}{5} = -1$$

=> $$m = -5$$

=> Ans - (A)


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