Solution
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Given : I is the incentre of $$\triangle$$ ABC and $$\angle$$ ABC = 90°
To find : $$\angle$$ AIC = $$\theta$$ = ?
Incentre of a triangle = $$90^\circ+\frac{1}{2} \times $$ (Angle opposite to it)
=> $$\theta=90^\circ+\frac{90^\circ}{2}$$
=> $$\theta=90^\circ+45^\circ$$
=> $$\theta=135^\circ$$
=> Ans - (A)
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