if $$\tan^{2} \alpha = 3 + Q^{2}$$ , then $$\sec \alpha + \tan^{3} \alpha \cosec \alpha=$$?

A

$$(3 + Q^{2} )^\frac{3}{2}$$

B

$$(7 + Q^{2} )^\frac{3}{2}$$

C

$$(5 - Q^{2} )^\frac{3}{2}$$

D

$$(4 + Q^{2} )^\frac{3}{2}$$