If $$\sec \theta + \tan \theta = 5, (\theta \neq 0)$$, then $$\sec \theta$$ is equal to:

A

$$\left(5 + \frac{1}{5}\right)$$

B

$$\frac{1}{2} \left(3 + \frac{1}{3}\right)$$

C

$$\frac{1}{2} \left(5 + \frac{1}{5}\right)$$

D

$$\left(3 + \frac{1}{3}\right)$$