Question 62

Out of 20 boys, 6 are each of 1 m 15 cm height, 8 are of 1 m 10 cm and rest of 1m 12cm. The average height of all of them is

Solution

Total number of boys = 20

Total height of first 6 boys = $$6\times1.15=6.9$$ m

Total height of next 8 boys = $$8\times1.10=8.8$$ m

Total height of last 6 boys = $$6\times1.12=6.72$$ m

=> Average height = $$\frac{(6.9+8.8+6.72)}{20}$$

= $$\frac{22.42}{20}=1.121=$$ 1m 12.1 cm

=> Ans - (B)

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