Question 62

If $$x + \frac{1}{x} = 8$$, then find the value of $$\frac{5x}{x^2 + 1 - 6x}$$

Solution

Given, $$x + \frac{1}{x} = 8$$

$$=$$> $$x^2+1=8x$$ ...............(1)

$$\therefore\ \frac{5x}{x^2+1-6x}=\frac{5x}{\left(x^2+1\right)-6x}=\frac{5x}{8x-6x}=\frac{5x}{2x}=2.5$$

Hence, the correct answer is Option B

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