Solution
Given, $$x + \frac{1}{x} = 8$$
$$=$$> $$x^2+1=8x$$ ...............(1)
$$\therefore\ \frac{5x}{x^2+1-6x}=\frac{5x}{\left(x^2+1\right)-6x}=\frac{5x}{8x-6x}=\frac{5x}{2x}=2.5$$
Hence, the correct answer is Option B
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