Two parallel chords are drawn in a circle of diameter 20 cm. The length of one chord is 16 cm and the distance between the two chords is 12 cm. The length of the other chord is:

Given,

Diameter of the circle = 20 cm

Radius of the circle = 10 cm

Distance between two chords = AC = 12 cm

Let the length of the other chord = 2a

From $$\triangle\ $$OAB,

$$OA^2+AB^2=OB^2$$

$$=$$>  $$OA^2+8^2=10^2$$

$$=$$>  $$OA^2+64=100$$

$$=$$>  $$OA^2=36$$

$$=$$>  $$OA=6$$

OC = AC - OA = 12 - 6 = 6 cm

From $$\triangle\ $$OCD,

$$OC^2+CD^2=OD^2$$

$$=$$>  $$6^2+a^2=10^2$$

$$=$$>  $$36+a^2=100$$

$$=$$>  $$a^2=64$$

$$=$$>  $$a=8$$ cm

$$\therefore\ $$Length of the second chord = 2a = 2(8) = 16 cm

Hence, the correct answer is Option C