If $$\triangle ABC \sim \triangle FDE$$ such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the
length of BC is:

A

$$5\frac{3}{4}$$ cm

B

$$4\frac{3}{5}$$ cm

C

$$3\frac{5}{7}$$ cm

D

$$6\frac{3}{4}$$ cm