If $$P \cos \alpha= 3$$ and $$4 \tan \alpha = Q$$, then what is the relation between P and Q, which is independent of $$\alpha$$?

A

$$\frac{9}{p^{2}} + \frac{16}{Q^{2}} = 1$$

B

$$\frac{9}{p^{2}} - \frac{16}{Q^{2}} = 1$$

C

$$\frac{p^{2}}{9} - \frac{Q^{2}}{16} = 1$$

D

$$\frac{p^{2}}{9} + \frac{Q^{2}}{16} = 1$$