If $$\frac{x}{y}=\frac{4}{9}$$, then what is the value of $$\frac{(7x^2-19xy+11y^2)}{y^2}$$ ?
Given : $$\frac{x}{y}=\frac{4}{9}$$
Let $$x=4$$ and $$y=9$$
To find : $$\frac{(7x^2-19xy+11y^2)}{y^2}$$
= $$\frac{7(4)^2-19(4)(9)+11(9)^2}{(9)^2}$$
= $$\frac{112-684+891}{81}$$
= $$\frac{319}{81}$$
=> Ans - (C)
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