Question 62

A man has some hens and some cows. If the total number of heads of hens and cows together is 50 and the nunber of feet of hens and cows together is 142, then the number of cows is

Let cows be x and hen be y 
we get x+y =50
4x+2y =142
solving we get x=21 and y=29
so cows =21

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