9 years ago,the average age of a family of five members was 33 years. Now, three new members join whose agesare in ascending order with consecutive gaps of 8 years. If the present average age ofthe family is the same as it was 9 years ago, whatis the age (in years) of the youngest new member ?

Let the sum of ages of 5 persons 9 years ago be S
so we get S = 33(5) = 165
Now sum of present ages of the 5 members = 165 +5(9) = 165+45 =210
Now let the ages of the three new members be a-8 , a and a+8 years
Now we can say the present average age of family is given as : 33 years
Also the number of members in the family are : 8
Therefore we can say the sum of present ages of 8 members of the family will be :
33(8) = 264 = 210+a-8+a+a+8
so we get 54 =3a
a=18 years
Now therefore age of youngest new member = 18-8 = 10 years