Solution
Given,
Side of the equilateral triangle (a) = $$4 \sqrt 3$$ cm
$$\therefore\ $$Area of the equilateral triangle = $$\frac{\sqrt{3}}{4}a^2$$
= $$\frac{\sqrt{3}}{4}\left(4\sqrt{3}\right)^2$$
= $$\frac{\sqrt{3}}{4}\times16\times3$$
= $$12 \sqrt 3 cm^2$$
Hence, the correct answer is Option B
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