Question 61

What is the area of an equilateral triangle of side $$4 \sqrt 3$$ cm?

Solution

Given,

Side of the equilateral triangle (a) = $$4 \sqrt 3$$ cm

$$\therefore\ $$Area of the equilateral triangle = $$\frac{\sqrt{3}}{4}a^2$$

= $$\frac{\sqrt{3}}{4}\left(4\sqrt{3}\right)^2$$

= $$\frac{\sqrt{3}}{4}\times16\times3$$

= $$12 \sqrt 3 cm^2$$

Hence, the correct answer is Option B

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