Question 61

The value of

$$3 \div 21 of 3 \times 7 + 24 \times 6 \div 18 - 3 \div 2 + 3 - 2 + 2 \times 3 \div 6$$ is:

Solution

$$3\div63\times7+24\times\frac{1}{3}-\frac{3}{2}+3-2+2\times\frac{1}{2}$$

$$\frac{1}{21}\times7+8-\frac{3}{2}+3-2+1$$

$$\frac{1}{3}+8-\frac{3}{2}+3-2+1$$

$$10+\frac{1}{3}-\frac{3}{2}$$

$$10+\frac{2}{6}-\frac{9}{6}$$

$$10-\frac{7}{6}$$

$$\frac{53}{6}$$

$$8\frac{5}{6}$$

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