Let O be the centre of a circle and AC be the diameter. BD is a chord intersecting AC at E. AD and AB are joined. If $$\angle BOC = 40^\circ$$ and $$\angle AOD = 120^\circ$$, then $$\angle BEC$$ is equal to:

A

$$55^\circ$$

B

$$80^\circ$$

C

$$90^\circ$$

D

$$70^\circ$$